Evaluate the sum 4+3+8+5+12+7+...to 32 Terms

Answers

• 

  Kiran M

  September 19, 2020

  We know the Sum of the First n terms of an Arithmetic Progression which is

  n/2[a + (n-1)d]

   

  The given series can be divided into two

  • 4+8+12...to 16 Terms
  • 3+5+7+...to 16 Terms

  There for

  4+8+12...16 where a = 4, d= 4

  Based on above equation summation of first series will be 16/2[4 + (16-1)4] = 512

   

  similarly 

  3+5+7+...to 16 where a = 3, d = 2

  then summation will be 16/2[3 + (16-1)2] = 264

   

  4+3+8+5+12+7+...to 32 Terms = 4+8+12...to 16 Terms + 3+5+7+...to 16 Terms

   

  so 512 + 264 = 776

   

  our Answer is 776

   

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