(1 + tan2A) / (1+cot2A)
Answers
Given L.H.S
= (1 + tan2A) / (1+cot2A)
We know sec2A - tan2A = 1
so sec2A = 1 + tan2A
Similarly cosec2A - cot2A = 1
cosec2A = 1 + cot2A
Now replace 1 + tan2A with sec2A and 1+cot2A with cosec2A
= sec2A / cosec2A
= (1/cos2A) / (1/sin2A)
= sin2A/cos2A
= tan2A
(1 + tan2A) / (1+cot2A)=tan2A