HackerRank Java IfElse Problem Solution
Published October 03, 2021In this Java example tutorial will explain about HackerRank Java IfElse Problem solution.
Java IfElse Challenge
Given an integer N perform the following conditional actions:
- If N is odd, print Weird
- If N is even and in the inclusive range of to , print Not Weird
- If N is even and in the inclusive range of to , print Weird
- If N is even and greater than , print Not Weird
Input Format
The Enter any number with in the range of 100
Constraints 1<=N<=100
Output Format
Print Weird if the number is weird; otherwise, print Not Weird
Solution
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class Solution {
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) {
int n = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
scanner.close();
if((1<=n)&&(n<=100)){
if(n%2==0)
{
if(((2<=n)&&(n<=5))||(n>20))
{
System.out.println("Not Weird");
}else if((6<=n)&&(n<=20))
{
System.out.println("Weird");
}
}else
{
System.out.println("Weird");
}
}
}
}
|
Input 3:
Output Weird
Article Contributed By :
|
|
|
|
270 Views |